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A slab of material of dielectric constan...

A slab of material of dielectric constant k has the same area A as the plates of a parallel plate capacitor and has thickness `(3d//4)`, where d is separation of the plates.The charge in capacitance when the slab is inserted between the plates is

A

`C=A_(epsilon0)/d((k+3)/(4k))`

B

`C=A_(epsilon0)/d((2k)/(k+3))`

C

`C=A_(epsilon0)/d((k+3)/(2k))`

D

`C=A_(epsilon0)/d((4k)/(k+3))`

Text Solution

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