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Calculate the rate of reaction from the ...

Calculate the rate of reaction from the following rate law:
`-(d[A])/(dt) = k[A]^(1)[B]^(2)`
when the concentrations of A and B are 0.01 M and 0.02 M respectively and `k=5.1xx10^(-3)L^(2)"mol"^(-2)s^(-1)`.

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`-(d[A])/(dt)=k[A]^(1)[B]^(2)`
Substituting the values of k, [A] and [B], we have
Rate of reaction `=5.1xx10^(-3) xx (0.01)(0.02)^(2)=5.1xx10^(-3)xx10^(-2)xx4xx10^(-4)`
`=20.4 xx 10^(-9) =2.04xx10^(-8)"mol L"^(-1)s^(-1)`
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Reaction A+BtoC+D is started with 1 M of each A and B and follows the rate law r=k[A]^(1//2)[B]^(1//2) What is the time taken for the concentration of A to drop to 0.1 M (K=2.303xx10^(-3)sec^(-1))

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