The rate constant for a first order reaction is 60 `s^(-1)`. How much time will it take to reduce 1 g of the reactant to 0.0625 g?

Explanation

The equation for a first order reaction is :
`t=(2.303)/(k)"log"([R]_(0))/([R])`
`[R]_(0)=1 g, [R]=0.0625 g, k=60s^(-1)`
Substituting the values in the first order equation, we have
`t=(2.303)/(60) "log"(1)/(0.0625)=(2.303)/(60)log 16=(2.303)/(60)xx1.204=0.0462s`