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The melting point of RbBr is 682^@C, wit...

The melting point of RbBr is `682^@C`, with that of `NaFis988^@C`. The principal reason that melting point of NaF is much higher than that of RbBr is that:

A

The two crystals are not isomorphous

B

The molar mass of NaF is smaller than that of RbBr

C

The internuclear distance `r_e+r_a` is greater for RbBr than for NaF

D

The bond is RbR has more covalent character than the bond in NaF

Text Solution

Verified by Experts

The correct Answer is:
C
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