When an electric current is passed simultaneously through acidulated water and copper sulphate soln.wt. of hydrogen and copper deposited are `0.0131 and 0.4164 gm` respectively. Calculate eq. mass of copper.

A current of 0.5 ampere is passed through acidulated water for 30 minutes. Calculate the wt. of H_2 and oxygen evolved ?

An electric current of 0.15 A is passed through 500mL of 0.15 M copper sulphate solution. How much time is required to deposit all the copper?

When a current of 0.75 ampere is passed through CuSO_4 for 25 mins, 0.369 g of copper is deposited at the cathode. Calculate the atomic mass of copper.

2.5 Faraday of electricity are passed through a solution of a solution of CuSO_4 . The Number of gram equivalents of copper deposited on the cathode are :

Electric current is passed through two cells A and B in series. Cell A contains aqueous solution of Ag_(2) SO_(4) and platinum electrodes. Cell B contains aqueous solution of CuSO_(4) and copper electrodes. The current is passed till 1.6g of oxygen is liberated at the anode in cell A. Calculate the quantities of copper and silver deposited at the cathode of the two cells. [ Atomic mass, O = 16, Cu 63.5, Ag = 108]

The amount of copper deposited by the passage of 96500 coulomb of electricity through copper sulphate solution is :