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Cu^(2+) +2e rarr Cu, log [Cu^(2+)] vs E(...

`Cu^(2+) +2e rarr Cu, log [Cu^(2+)]` vs `E_(red)`.graph is of the type as shown in figure where `OA =0.34 V` then electrode otential of the half cell of `Cu^(2+)(0.1M)` will be :

A

`-0.34+0.091/2 V`

B

`0.34 + 0.0591V`

C

`0.34V`

D

None

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The correct Answer is:
A
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