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Inversion of a sugar follows first order...

Inversion of a sugar follows first order rate equation which can be followed by noting the change in rotation of the plane of polarization of light in the polarimeter `if r_infty`,`r_t` and `t=oo`, t=t and t=0, then, first order reaction can be written as:

A

`K=1/t"log_e"(r_1-r_infty)/(r_0-r_infty)`

B

`K=1/tIn(r_0-r_oo)/(r_t\-r_oo)`

C

`K=1/tIn(r_oo-r_0)/(r_oo\-r_t)`

D

`K=1/tIn(r_oo-r_1)/(r_oo\-r_0)`

Text Solution

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The correct Answer is:
B
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