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The rate for a first order reaction is 0...

The rate for a first order reaction is `0.6932 xx 10^(-2)mol L^(-1) min^-1` and the initial concentration of the reactant is 1 M, `t_(1//2)` is equal to:

A

`0.6932 x 10^(-2)minute`

B

`0.6932 x x10^(-2)`

C

100minute

D

6.932minute

Text Solution

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The correct Answer is:
C
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