A stationary body of mass 3 kg explodes into three equal pieces. Two of the pieces fly off at right angles to each other, one with a velocity `2hati` m/s and the other with a velocity `3hatj` m/s. If the explosion takes place in `10^(-5)` s, the average force acting on the third piece in newton is

Options

A. `(2hati + 3hatj)xx 10^5`
B. `-(2hati + 3hatj)xx 10^5`
C. `(3j - 2i )xx 10^-5`
D. `(2hati - 3hatj ) xx 10^-5`