Home
Class 11
PHYSICS
The dispersive power (omega) of the mate...

The dispersive power `(omega)` of the material of prism is given by

A

`omega = frac A(n_v-n_r)(n_y-1)`

B

`omega = frac(n_v-n_r)(A(n_y-1)`

C

`omega = frac(n_v + n_r)(n_y - 1)`

D

`omega = frac(n_v - n_r)(n_y -1)`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • Motion in a plane

    TARGET PUBLICATION|Exercise Exercise|340 Videos
  • RAY OPTICS

    TARGET PUBLICATION|Exercise EVALUATION TEST|16 Videos

Similar Questions

Explore conceptually related problems

The refractive index of the prism for violet colour is 1.7 and that for red is 1.65. Then dispersive power of the material of prism is

The refractive index of the prism for violet colour is 1.7 and that for red is 1.65. Then dispersive power of the material of prism is

The refractivity of the material of the prism is given by

The refractivity of the material of the prism is given by

Dispersive power depend upon

Define Dispersive Power.

A spectrum is formed by a prism of dispersive power omega . If the angle of deviation is delta . Then the angular dispersion is

From the given data set, determine angular dispersion by the prism and dispersive power of the material for extreme colours. n_R = 1.62, n_v = 1.66, s_R = 3.1^@

A ray of light is incident at an angle of 60^(@) on the face of a prism with an angle of 60^(@) . Then the refractive index of the material of the prism is (the prism is in minimum deviation position)

The refractive index of the material of a prism is sqrt(2) and the angle of the prism is 30^(@) .One of the two refraction surfaces of the prism is made a mirror inwards, by silver coating. A beam of monochromatic light entering. The prism from the other face will retrace its path ( after reflection from the silvered surface ) if its angle of incidence on the prism is