A thin glass rod is bent into a semicircle of radius r. A charge +Q is uniformly distributed along the upper half and a charge -Q is uniformly distributed along the lower half, as shown in fig. The electric field E at P, the center of the semicircle, is

A thin glass rod is bent into a semicircle of radius r. A charge +Q is uniformly distributed along the lower half, as shown in fig. The electric field E at P, the center of the semicircle, is

Charges q is uniformly distributed over a thin half ring of radius R . The electric field at the centre of the ring is

A charge Q is uniformly distributed only on the fourths portion of a ring of radius R . The elctric potential at centre of ring is

A wire of length l and charge q is bent in form of a semicircle. The charge is uniformly distributed over the length. The electric field at the centre of semicircle is

Calculate potential on the axis of a ring due to charge Q uniformly distributed along the ring of readius R.

A plastic rod has been formed into a circle of radius R. It has a positive charge +Q uniformly distributed along one-quarter of its circumference and a negative charge of -6Q uniformly distributed along the rest of the circumference (figure). With V = 0 at infinity, what is the electric potential -6Q (a) at the centre C of the circle and (b) at point P, which is on the central axis of the circle at distance z from the centre?

A spherical shell of radius R has a uniformly distributed charge ,then electric field varies as

Calculate potential on the axis of a disc of radius R due to a charge Q uniformly distributed on its surface.

A positive charge Q is uniformly distributed across a rod of length L. The rod is then bent in the form of a semicircle. What will be the electric field intensity at the centre of curvature of the semicircle thus formed?

There is a hemispherical shell having charge Q uniformly distributed on its surface. Radius of the shell is R. Find electric potential and field at the centre (of the sphere).