IF `z(z in C)` satisfy `abs(z+5)le5 and z(1+i)+barz(1-i)ge-10`.If the maximum value of `abs(z+1)^2` is `alpha+sqrt2beta ` then find `alpha+beta`

Let z be those complex numbers which satisfy |z+5| =-10 i= sqrt(-1) If the maximum value of |z+1|^(2) is alpha+beta sqrt(2) , then the value of (alpha+beta) is

if |z-2i| le sqrt2 , then the maximum value of |3+i(z-1)| is :

abs(z-(3i+2)) le2 then find the min value of abs(2z-6+5i)

If z is a complex number such that abs(z)le1 then minimum value of abs(z+1/2(3+4i)) is equal to

If z is any complex number satisfying abs(z-3-2i) le 2 , where i=sqrt(-1) , then the minimum value of abs(2z-6+5i) , is

If z satisfies the equation ((z-2)/(z+2))((barz-2)/(barz+2))=1 , then minimum value of |z| is equal to :