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Ethyl benzene on heating with Cl2 gives ...

Ethyl benzene on heating with `Cl_2` gives `A(C_8 H_9CI)`. A on reaction with alcoholic KOH gives `B(C_8 H_8)`. Compounds A and B are, respectively

A

`C_6H_5 - CH_2CH_2 Cl and C_6H_5 - CH_2 - CH_2-OH `

B

`C_H_5 - overset(Cl)overset(|)CH-CH_3 and C_6H_5-overset(OH)overset(|)CH-CH_3`

C

`C_6H_5 - CH_2CH_2Cl and C_6H_5-CH =CH_2`

D

`C_6H_5 - overset(Cl)overset(|)CH-CH_3 and C_6H_5 - CH = CH_2 `

Text Solution

Verified by Experts

The correct Answer is:
D
Free radical chlorination occur at benzylic carbon followed by E-2 elimination reaction
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