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An alkane with mol.mass = 86 on brominat...

An alkane with mol.mass = 86 on bromination gives only two monobromo derivatives (excluding stereoisomers). The alkane is

A

`(CH_3)_2CHCH_2CH_2CH_3`

B

`(CH_3)_3C-CH_2CH_3`

C

`(CH_3)_2CH-CH(CH_3)_2`

D

`(CH_3)_4C`

Text Solution

Verified by Experts

The correct Answer is:
C
The alkane with mol. Mass 86 is hexane `(C_6H_(14))` 2,3-Dimethylbutane, i.e., Option (c) has only two types of hydrogens and hence forms two monobromo derivatives
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