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CH3- underset(CH3)underset(|)C=CH2 + HCl...

`CH_3- underset(CH_3)underset(|)C=CH_2 + HCl overset((C_6H_5CO)_2O_2)to X `(major) here 'X' is

A

`(CH_3)_2C(Cl)-CH_3`

B

`(CH_3)_2 CHCH_2Cl`

C

`ClCH-2-underset(CH_2Cl)underset(|)(CH)-CH_3`

D

`CH_3-underset(CH_2Cl)underset(|)overset(Cl)overset(|)C-CH_3`

Text Solution

Verified by Experts

The correct Answer is:
A
`CH_3-underset(CH_3)underset(|)C=CH_2 + H - Cl to CH_3 - underset(CH_3)underset(|)overset(Cl)overset(|)C - CH_3`
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