Home
Class 11
CHEMISTRY
The reaction of acetylene and propyne w...

The reaction of acetylene and propyne with `HgSO_4` in presence of `H_2SO_4` produces respectively

A

acetone and acetladehyde

B

acetaldehyde and acetone

C

propionaldehyde and acetone

D

acetone and propionaldehyde

Text Solution

Verified by Experts

The correct Answer is:
B
Acetylene gives acetaldehyde while propyne gives acetone
Promotional Banner

Similar Questions

Explore conceptually related problems

When propyne is treated with aqueous H_2SO_4 in the presence of HgSO_4 . the major product is

The reaction between carboxylic acid and an alcohol in the presence of con. H_2 SO_4 to form sweet smelling substance is called

Heating a mixture of ethyl alcohol acetic acid in presence of conc. H_2SO_4 produces a fruity smelling compounds A . Then A is

Decomposition of oxalic acid in the presence of conc. H_(2)SO_(4) gives

When acetylene is passed through dil. H_(2)SO_(4) in the presence of the HgO_(4) , the compound formed is

The products formed during the reaction of carbon with conc. H_(2)SO_(4) are C+H_(2)SO_(4)to products

When acetylene gas is passed through dilute H_(2)SO_(4) in presence of Hg^(2+) ions, compound A is formed, which then undergoes rearrangement to give the product B. Write the complete equation and name the products A and B.

Passage - VI : Industrially sulphuric acid is produced by the following steps: Stage I : S+O_(2) overset(Delta)to SO_(2) Stage II : 2SO_(2) +O_(2) overset(V_(2)O_(5))to 2SO_(3) Stage III : SO_(3)+H_(2)O to H_(2)SO_(4) Since the reaction between SO_(3) and H_(2)O is violent, SO_(3) is passed into 98% H_(2)SO_(4) to produce oleum (H_(2)S_(2)O_(7)) Pure H_(2)SO_(4) does not react with metal because -

Passage - VI : Industrially sulphuric acid is produced by the following steps: Stage I : S+O_(2) overset(Delta)to SO_(2) Stage II : 2SO_(2) +O_(2) overset(V_(2)O_(5))to 2SO_(3) Stage III : SO_(3)+H_(2)O to H_(2)SO_(4) Since the reaction between SO_(3) and H_(2)O is violent, SO_(3) is passed into 98% H_(2)SO_(4) to produce oleum (H_(2)S_(2)O_(7)) Ionically the reaction between H_(2)SO_(4) & Mg may be presented as, Mg+2H_(3)O^(+) to Mg^(2+)+H_(2) uarr +2H_(2)O Therefore, in the given reaction -