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0.37 gm of alcohol when treated with CH3...

0.37 gm of alcohol when treated with `CH_3MgI` liberates 112 ml of `CH_4` at STP. The molecular formula of alcohol is

A

`C_4H_9OH`

B

`C_5H_(11)OH`

C

`C_3H_7OH`

D

`C_2H_5OH`

Text Solution

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The correct Answer is:
A
Molecilar formula
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