Home
Class 11
CHEMISTRY
The number of geometrical isomers of A c...


The number of geometrical isomers of A can be

A

2

B

3

C

4

D

5

Text Solution

Verified by Experts

The correct Answer is:
C

Proceeding reverse, the structure of A is

One asymmetric carbon `to` two optical isomers one ( C = C) with different group `implies` two geometrical isomers
`:.` Total no of stereoismers : 4 .
Promotional Banner

Similar Questions

Explore conceptually related problems

Report the number of geometrical isomers and ebentiomeric pairs of the complex [PtCl_(2)(NH_(3))_(2)(Py)_(2)]^(2+) .

Consider the complexs. (i) [Pd(NH_(3))_(2)ClBr] [Pd(NH_(3))_(2)Cl_(2)] [Pd(en)Cl_(2)] [Pd(en)ClBr] [Pd(en)_(2)]Cl_(2) " (en = ethylenediamine)" The total number of geometrical isomers of (a) is same as the total number of geometrical isomers of

CH_(3)-CH=C=CH-CH_(3) The possible number of geometrical isomers of this diene is_________

The number of geometrical isomers of [Co(NH_(3))_(3)(NO_(3))_(3)] is

The number of geometrical isomers of CH_3CH=CH-CH-CH=CH-Cl

The possible number of geometrical isomers for this compound which can be isolated at room temperature is

Find out maximum number of geometrical isomers theoritically possible for an actaheral complex of formula [Pt(en)(NH_(3))_(2)Cl_(2)(en)^(+)] are

CH_3 - CH =undersetoverset(|)( C)(C ) - undersetoverset(|)(C )(C ) = CH - CH_3 Number of geometrical isomers possible for this compound are