Chlorine is prepared in the laboratory by treating manganese dioxide `(MnO_(2))` with aqueous hydrochloric acid according to the reaction :
`4 HCl_((aq)) + MnO_(2(s)) rarr 2H_(2)O_((l)) +MnCl_(2(aq)) + Cl_(2(g))`
How many grams of HCl react with 5.0 g of manganese dioxide ?

Explanation

`4HCl_((aq)) +MnO_(2(s)) rarr 2H_(2)O_((l)) + MnCl_(2(aq)) + Cl_(2(g))`
`4 xx 36.5 " "87`
`87 g MnO_(2) = 4 xx 36.5 g HCl`
`5 g Mno-(2) = " " (?)`
`= (4xx36.5 xx 5)/(87) = 8.39` gm HCl
For complete reaction of 87 gm` MnO_(2)`,
8.39 g HCl