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How many moles of solute are required in...

How many moles of solute are required in 300 g solvent to prepare 3 molal solution ?

A

0.01

B

1

C

0.09

D

0.9

Text Solution

Verified by Experts

The correct Answer is:
D
`=("weight of solute (gm)")/("molecular mass " xx "wt. of solvent in kg")`
` 3 = ("mole")/("weight of solvent")`
`= ("male")/(0.300)`
Mole `= 3 xx 0.3 = 0.9`
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