How many moles of `Mg_(3)(PO_(4))_(2)` consists 0.25 mole oxygen atoms ?

Options

A. `2.55xx10^(-2)`
B. `0.0225`
C. `3.125xx10^(-2)`
D. `1.5xx10^(-2)`

Answer

A, B, C

Explanation

1 mole `Mg_(3)(PO_(4))_(2)` consists 8 mole .O. atoms
8 mole atoms in 1 mole `Mg_(3)(PO_(4))_(2)`
`:.0.25` mole atoms `= (?)`
`=(0.25xx1)/(8) = 0.03125 = 3.125xx10^(-2)` mole