The density ( in g `mL^(-1)` ) of 3.60 sulphuric acid solution that is 29 % `H_(2)SO_(4)` (Molar mass `= 98 g mol^(-1)` ) by ,mass will be

Options

A. 1.64
B. 1.88
C. 1.22
D. 1.45

Answer

A, B, C

Explanation

`M= 3.6 mol L^(-1)`
`:.` 3.6 mole `H_(2)SO_(4)` in 1000 mL solution
`:.` 1000 mL solution of `H_(2)SO_(4)` contains
`(3.6xx98) g ` of `H_(2)SO_(4)`
The solution is 29% by mass
`1:.` 100 g solution contains 29 g of `H_(2)SO_(4)`
`:.` If `H_(2)SO_(4) 3.6 xx 98 g`
Weight of solution `= (3.6xx 98xx 100)/(29)` g
Density (d) `= ("wt of solution")/("volume of solution")`
`= (3.6xx 98xx100)/(29 xx 1000) = (3.6xx98)/(290)`
`= 1.2166`
`= 1.22 g mL^(-1)`