In the reaction of sodium thiosulphate with `I_(2)` in aqueous medium the equivalent weight of sodium thiosulphate is equal to

Options

A. Molar mass of sodium thiosulphate
B. The average of molar masses of `Na_(2)S_(2)O_(3)` and `I_(2)`
C. Half the molar mass of sodium thiosulphate
D. Molar mass of sodiu thiosulphate `xx 2`

Answer

A, D

Explanation

`2Na_(2)S_(2)O_(3)*5H_(2)O + I_(2) rarr 2NaI + Na_(2) S_(4) O_(6)` or
`:.2S_(2)O_(3)^(3-) rarr S_(4)O_(6)^(2-) +2e^(-)`
Equivalent weight of `Na_(2)S_(2)O_(3) . 5H_(2)O`
`= ("Mol. Wt.")/(1) = (248)/(1) = 248`