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Combustion of a gaseous hydrocarbon give...

Combustion of a gaseous hydrocarbon give 0.25 g water. What will be empricial formula of the hydrocarbon ?

A

`C_(2)H_(4)`

B

`C_(2)H_(6)`

C

`C_(3)H_(4)`

D

`C_(7)H_(8)`

Text Solution

Verified by Experts

The correct Answer is:
C, D
`H_(2)O = 0.72 g = (0.72)/(18) = 0.04 "mole" H_(2)O`
`CO_(2) = 3.08g = (3.08)/(44) = 0.07 "mole" CO_(2)`
`:.` Mole of `C= 0.07`
`:.` Mole of `H = 2 (0.04)= 0.08`
`:.` Proportion of `C : H`
`= 0.07 : 0.08`
Empirical formula `=C_(7)H_(8)`
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