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1.0 g of magnesium is burnt with 0.56 g ...

1.0 g of magnesium is burnt with 0.56 g `O_(2)` in a closed vessel. Which reaction is left in excess and how much ? ( At. wt. Mg `= 24, O = 16`)

A

`Mg, 0.16 g `

B

`O_(2), 0.16 g`

C

`Mg, 0.16 g`

D

`O_(2), 0.28 g`

Text Solution

Verified by Experts

The correct Answer is:
A
`M g + 1/2 O_(2) rarr MgO`
`(1.0)/(24) (0.56)/(32)`
Oxygen is limiting reagent so `(0.5)/(12) - x(0.07)/(4) - x/2`
`(0.07)/(4) - x/2 = 0`
`x=(0.07)/(2)`
excess `Mg=(0.5)/(12) - (0.07)/(2)` mole
`rArr 1-0.7xx12= 0.16g`
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