The concentration of `Al^(3+)` ion in aqueous solution of `Al_(2)(SO_(4))_(3)` is 0.28 M
Then the concentration of `SO_(4)^(2-)`
ion in this solution will be:

Options

A. 0.28 M
B. 0.042 M
C. 0.42 M
D. 0.84 M

Answer

B, C, D

Explanation

Ionisation of `Al_(2)(SO_(4))_(3)` in its aqua solution
`Al_(2)(SO_(4))_(3) overset(H_(2)O)rarr 2Al_((aq))^(3+) + 3SO_(4(aq))^(2-)`
According to stochiometry of the reaction `2Al^(3+)` ions and `3SO_(4)^(2-)` ions are formed.
`SO_(4)^(2-)` ions `=(0.28xx3)/(2) = 0.42 M`