A 0.50 g `H_(2)SO_(4)` is dissolve in 0.25 L solution, so find out the normality and molarity respectively of the solution.
`(H=1, S= 32, O=16)`

Options

A. 0.040, 0.020
B. 0.4, 0.2
C. 0.020, 0.040
D. 0.2, 0.4

Answer

A, B, D

Explanation

Molarity `=("Mass of solute(gm)")/("Moleculer weight of solute" xx "Volume of solution(litre)")`
`= (0.50)/(98xx0.5) = 0.020`
`N= Mxx2 = 0.020xx2= 0.040`