What will be normality of the solution of the mixture of 40 mL, 0.2 M `H_(2)SO_(4(aq))` and 60 mL `0.3 M H_(2)SO_(4(aq))` ?

Options

A. 0.26 N
B. 0.25 N
C. 0.5 N
D. 0.52 N

Answer

B, D

Explanation

`M_(3) = (M_(1)V_(1)+M_(2)V_(2))/(V_(3))`
`= ((40xx0.2) + (60xx0.3))/(100)`
`= (8.0+ 18.0)/(100)`
`= 0.26M`
Where :
`{:(M_(1)=0.2M),(V_(1)=40mL):}}H_(2)SO_(4)`
`{:(M_(2)=0.3M),(V_(2)=60mL):}}H_(2)SO_(4)`
`v_(3)=(60+40)mL`
`= 100 mL`
`M_(3)=` Morality of mix solution
` 0.26 =` Molarity of mixed `H_(2)SO_(4)` solution
Molecular mass of `H_(2)SO_(4) = 2(H) + S + 4 (O)`
`= 2(1) + 32+4(16)`
`= 98g*mol^(-1)`
Basicity of `H_(2)SO_(4) = 2= ` no. of `H^(+)`
`:.` Equivalent wt. of `H_(2)SO_(4)= 98//2=49`
Normality `=("Molarity" xx "Molecular weight")/("Equivalent weight")`
`= 0.26xx98)/(49) = 0.52 N H_(2)SO_(4)`