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Hydrogen gas is perpared in the laborato...

Hydrogen gas is perpared in the laboratory by reacting dilute HCl with granulated zinc. Following reaction takes place.
`Zn+2HCl rarr ZnCl_(2) +H_(2)`
Calculate the volume of hydrogen gas liberated at STP when 32.65 g of zinc reacts with HCl. 1 mol of a gas occupies 22.7 L volume at STP, atomic mass of `Zn= 65.3 u`.

Text Solution

Verified by Experts

Mass of `Zn= 32.65 g` (given)
1 mole of gas `= 22.7` L volume at STP
Atomic mass of `Zn= 65.3u`
The given equation is
`{:(Zn+2HClrarrZnCl_(2)+H_(2)),(65.3g" 1 mol "= 22.7 L " at STP"):}`
from the above equation
65.3 g Zn, when reacts with HCl, produces `=22.7 L` of `H_(2)` at STP.
`:.` 32.65 g Zn, when reacts with HCl, will produce `=(22.7xx32.65)/(65.3) = 11.35L` of `H_(2)` at STP.
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