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The density of 3 molal solution of NaOH ...

The density of 3 molal solution of NaOH is 1.110 g `mL^(-1)` . Calculate the molarity of the solution.

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3 molal solution of NaOH means 3 moles of NaOH are dissolved in 1 kg solvent.
So, the mass of solution `=1000g` solvent `+` 120 g
`NaOH = 1120` g solution
(Molar mass of `NaOH = 23 + 16+1= 40 g` and
3 moles of `NaOH= 3 xx 40 = 120g` )
Volume of solution `=("Mass")/("Density")`
`V=(1120g)/(1.110g mL^(-1))= 1009 ` mL
Molarity `= ("Moles of solute"xx1000)/("Volume of solution(mL)")`
`= (3xx1000)/(1009) ~~3M`
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