In which case is the number of molecules of water maximum ?

Options

A. `10^(-3)` mole of water
B. 18 ml of water
C. 0.00224 L of water vapours at 1 atm and 273 K
D. 0.18 g of water

Answer

B

Explanation

(A) `10^(-3)` mole water
(B) 18 ml water = 18 g water = 1 mol water
(C) 0.00224 L water vapour at (STP)
`(0.00224)/(22.4) = 0.0001` mole `H_2O`
(D) 0.18 g water = `(0.18)/( 18) = 0.1 ` mol water
Among the four options, option (B) has maximum number of moles so it has maximum molecules.