`1/(x+1)+2/(x+2)=4/(x+4) , x!=-1 , x!=-2 , x!=-4`

Solve for x : 1/(x+1)+2/(x+2)=4/(x+4) , x!=1, -2, -4

Solve for x:(1)/(x+1)+(2)/(x+2)=(4)/(x+4),quad x!=1,-2,-4

((4x-3) / (2x + 1))-10 ((2x + 1) / (4x-3)) = 3, x! =-1/2, 3/4

(2x + 1) / (x) + (4x) / (2x + 1) = 5

The factor of x^8 + x^4 +1 are (A) (x^4 + 1 - x^2), (x^2 +1 +x), (x^2 + 1 - x ) (B) x^4 + 1 -x^2 , (x^2 - 1 + x), (x^2 +1 + x) (C ) (x^4 - 1 + x^2, (x^2 - 1 + x), (x^2 + 1 + x) (D) (x^4 -1 + x^2), (x^2 + 1 - x), (x^2 + 1 +x)

Solve for :x:(x-1)/(x-2)+(x-3)/(x-4)=3(1)/(3),x!=2,4

lim_ (x rarr (1) / (2)) ((8x-3) / (2x-1) - (4x ^ (2) +1) / (4x ^ (2) -1))

If x-1/x=2 then x^4-1/x^4=