Home
Class 11
PHYSICS
Consider a small sphere falling through ...

Consider a small sphere falling through a medium. The viscous force acting on the sphere depends upon the radius (r) of the sphere, velocity (V) of the sphere and the co-efficient of viscosity `(eta)` of the medium. Use dimensional analysis and show that the viscous force is directly proportional to `etarv`.
(Given : Dimensions of `eta =[M^1L^-1T^-1])`.

Promotional Banner

Topper's Solved these Questions

  • Unit Test 3

    CHETANA PUBLICATION|Exercise EXERCISE|20 Videos

Similar Questions

Explore conceptually related problems

Calculate the viscous force acting on a rain drop of diameter 1mm, falling with a uniform velocity 2 m//s through air. The coefficient of viscosity of air is 1.8 xx 10^-5 Ns//m^2 .

Viscous force on a small sphere of radius r moving in a fluid varies directly with

Water drop of radius 0.3 mm is falling through air is 18 xx 10^(-5) kg m^(-1)V^(-1) , then the viscous force acting on the drop will be

A small steel ball of mass m and radius r is falling under gravity through a viscous liquid of coefficient of viscosity eta . If g is the value of acceleration due to gravity. Then the terminal velocity of the ball is proportional to (ignore buoyancy)

Spherical balls of radius 'R' are falling in a viscous fluid of viscosity 'eta' with a velocity 'v'. The retarding viscous force acting on the spherical ball is

Spherical balls of radius 'r' are falling in a viscous fluid of viscosity eta with a velocity 'v' .The retarding viscous force acting on the spherical ball is

A steel ball with radius 0.3mm is falling with velocity of 2 m//s at a time t, through a tube filled with glycerin, having coefficient of viscosity 0.833 Ns//m^2 . Determine viscous force acting on the steel ball at that time.

A heavy brass sphere is hung froma weightless inelastic string and used as a simple pendulum. Its time period of osciallation is T. When the shere is immersed in a non-viscous liquid of density (1)/(10) that of brass. If acts as a simple perpendicular of period.

CHETANA PUBLICATION-UNITS AND MEASUREMENTS-EXERCISE
  1. v = at + frac(b)(t+c) + v0 is dimensionally valid equation Obtain the ...

    Text Solution

    |

  2. Check weather the equation is dimensionally correct v^2 = u^2 + 2as^2.

    Text Solution

    |

  3. Consider a small sphere falling through a medium. The viscous force ac...

    Text Solution

    |

  4. Assume that the speed (v) of sound in air depends upon the pressure (P...

    Text Solution

    |

  5. If length 'L', force 'F' and 'T' are taken as fundamental quantities, ...

    Text Solution

    |

  6. The density of mercury is 13.6 g//cm^3 using dimensional analysis expr...

    Text Solution

    |

  7. An object is falling freely under the gravitational force. Its velocit...

    Text Solution

    |

  8. Find dimensions of permittivity of vacuum, if F=frac(1)(4pi epsilon0) ...

    Text Solution

    |

  9. List the reasons for arising uncertainties in observations.

    Text Solution

    |

  10. What is an error explain types of error.

    Text Solution

    |

  11. What are the methods to minimise errors?

    Text Solution

    |

  12. Define. (i) Most probable value. (ii) Absolute error. (iii) Relati...

    Text Solution

    |

  13. The masses of two bodies are measured to be 15.7 +- 0.2 kg and 27.3 +...

    Text Solution

    |

  14. The side of an object measured by means of a vernier callipers is 3.52...

    Text Solution

    |

  15. The distance travelled by an object in time (100+-1)s is (5.2+-0.1)m. ...

    Text Solution

    |

  16. In a workshop a worker measures the length of a steel plate with a Ver...

    Text Solution

    |

  17. If the measured values of two quantities are A +- Delta A and B +- Del...

    Text Solution

    |

  18. Find the percentage error in kinetic energy of a body having mass 60.0...

    Text Solution

    |

  19. In ohm's experiment, the values of unknown resistances were found to b...

    Text Solution

    |

  20. If the length of a cylinder is l = (4.00 +-0.001) cm, radius r=(0.025 ...

    Text Solution

    |