At wich point of its trajectory does the projectile have minimum speed?

At which point of the trajectory does projectile have minimum velocity?

At the highest point of the path of a projectile,

A projectile is fired from the surface of the earth with a velocity of 7 ms^-1 and angle theta with the horizontal. Another projectile fired from another planet with a velocity of 2.5 ms^-1 at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet is (in ms^-1 (given =9,8 ms^-2 )

A projectile is launched at an angle of theta above the horizontal The elevation angle alpha of the highest point of the trajectory as seen from the launching position is given by

A particle of mass m is projected from the ground with an initial speed u_0 at an angle alpha with the horizontal. At the highest point of its trajectory, it makes a completely inelastic collision with another identical particle, which was thrown vertically upward from the ground with the same initial speed u_0. The angle that the composite system makes with the horizontal immediately after the collision is

The horizontal distance between the point of projection and the point on the same horizontal plane, at which, the projectile returns after moving along its trajectory, is called _____ of the projectile.

A body of mass m tied to a string of length r is at its lowest position. What should be the minimum speed given to it so as just to complete one revolution ?

Show that the trajectory of a projectile is a parabola, which can be expressed as y = bx - cx^2

On what does the speed of mechanical waves depend?

The initial velocity of the projectile is u and its maximum range is R_max then u is given by