Define: Horizontal Range and Time of flight.

Define molecular Range .

Two particles are projected from the same point with the same speed, at different angles theta_1 and theta_2 to the horizontal. Their times of flight are t_1 and t_2 respectively and they have the same horizontal range. Then the incorrect relation is

Define horizontal range. Derive the necessary expression for it.

A stone thrown at an angle to theta with the horizontal reaches a maximum height H. Then the time of flight of stone will be

Neglecting the air resistance, the time of flight of a projectile is determined by

A shell is fired from canon with a velocity of 200 m/s at an angle of 30^@ with the horizontal The horizontal range attained by it is [g= 10 m s^-2]

The maximum height attained by projectile is increased by 10%, by changing the angle of projection, without changing the speed of projection. The percentage increase in the time of flight will be

A projectile can have the same range R for two angles of projection. If t_1 and t_2 are the times of flight in the two cases, then the product of the two time of flight is proportional to A. R^2 B. frac(1)(R^2) C. frac(1)(R) D. R

At the point of horizontal range (R), the coordinates are

A body is projected with a vertical velocity of 30 m//s at an angle of 30^@ with the horizontal, the maximum height and horizontal range are respectively