Locate the centre of mass of the syste,m of three particles of masses `m_1 = 1` kg, `m_2 = 2`kg and `m_3 = 3` kg which are placed at the corners of an equilateral triangle of side 1 m.

Three equal masses each of 1 kg are placed at vertices of an equilateral triangle of side 10m. Find the position of centre of mass.

Choose the correct options The centre of mass of a system of two uniform spherical masses of 5 kg and 35 kg with centres of them 0.7 m apart is

Three particles of masses1kg, 2 kg and 3 kg are at distances 1 m, 2 m and 3 m from the axis of rotation. The moment of inertia of the system is

Consider a sytem of two particles having masses m_(1) and m_(2) . If the particle of mass m_(1) is pushed towards the centre of mass of particles through a distance d , by what distance would the particle of mass m_(2) move so as to keep the mass centre of particles at the original position?

Three point masses, each of mass.2 kg are placed at the corners of an equilateral triangle of side 2 m. What is moment of inertia of this system about an axis along one side of the triangle ?

Centre of mass of 3 particles 10 kg, 20 kg and 30 kg is at (0, 0, 0). Where should a particle of mass 40 kg be placed so that the combination centre of mass will be at (3,3,3)

A mass M is broken into two parts of masses m_(1) and m_(2) . How are m_(1) and m_(2) related so that force of gravitational attraction between the two parts is maximum?

A mass M is broken into two parts of masses m_(1) and m_(2) . How are m_(1) and m_(2) related so that force of gravitational attraction between the two parts is maximum?

Two particles of mass m_(1) and m_(2) , approach each other due to their mutual gravitational attraction only. Then

Three point masses each of mass m are placed at the corners of an equilateral triangle of side 'a'. Then the moment of inertia of this system about an axis passing along one side of the triangle is