Find the position vector of the centre of mass 1 kg, 2 kg and 3 kg at points `(3hati + 2hatj).(5hatj + hatk)` and `(2hati + hatk)` respectively.

The position vectors of the point A, B, C and D are 3hati-2hatj -hatk, 2hati+3hatj-4hatk, -hati+hatj+2hatk and 4hati+5hatj +lamda hatk , respectively. If the points A, B, C and D lie on a plane, find the value of lamda . a) 146/17 b) -146/17 c) -17/146 d) 17/146

If the position vectors of the vetrices of a triangle be 6hati+4hatj+5hatk , 4hati+5hatj+6hatk and 5hati+6hatj+4hatk ,then he triangle is

The value of (hati+hatj).[(hatj+hatk)xx(hatk+hati)] is

The vector equation of a plane passing through three points hati+hatj-2hatk, 2hati-hatj+hatk" and " hati+2hatj+hatk is

Position vectors of a point which divides line joining points A and B whose position vectors are 2hati+hatj-hatk and hati-hatj+2hatk externally in the ratio 5:2 is

If 3hati-2hatj+5hatk and -2hati+phatj-qhatk are collinear vectors,then

The vector equation of the line passing through (2, 1, -1) and parallel to hati+2hatj+hatk is

If the position vectors of the points A and B are hati+3hatj-hatk and 3hati-hatj-3hatk, then what will be the position vectors of the mid point of AB

Show that vectors veca= 2hati+5hatj-6hatk and vecb=hati+5/2 hatj -3hatk are parallel.

The cartesian equation of the line barr = (hati + hatj + hatk)+ lambda(hatj + hatk) is