What happens to K.E. of satellite as it moves away from the surface of the earth?

The escape velocity of a body from the surface of the earth is equal to

The escape velocity of a body from the surface of the earth is V_e and the escape velocity of the body from a satellite orbiting at a height 'h' above the surface of the earth is v_e ' then

An artificial satellite makes two revolutions per day around the earth. If the acceleration due to gravity on the surface of the earth is 9.8 m//s^2 and the radius of the earth is 6400 km, calculate the distance of satellite from the surface of the earth

Calculate the period of revolution of a polar satellite orbiting close to the surface of the Earth.

The rotation period of an earth satellite close to the surface of the earth is 83 minutes. The time period of another earth satellite in an orbit at a distance of three earth radii from its surface will be

Solve the following examples/numerical problems : Calculate the critical velocity (Vc) of the satellite to be located at 2000 km above the surface of the earth?

A stone is dropped from a height equal to nR , where R is the radius of the earth, from the surface of the earth. The velocity of the stone on reaching the surface of the earth is

A satellite is going in a circular orbit of radius 4 xx 10^5 km around the earth has a certain speed. (b) What will be the ratio of the weight of a body on the surface of Mars to tyhe weight of the same body on the surface of the earth? The masses of earth and Mars are in the ratio 10:1 and their radii are in the ratio 2:1

Answer the following questions : What is the acceleration due to gravity at a height h (=radius of the earth) from the surface of the earth ? (g=9.8m/s^2)

Derive an expression for critical velocity of satellite. Calculate the acceleration due to gravity at a height of 300 km from the surface of the earth. M = 6xx10^24kg R = 6400 km.