A satelite is revolving in a circular orbit at a height h above the surface of the earth of radius R. The speed of the satellite in its orbit is one-fourth the escape velocity from the surface of the earth. The relation between h and R is

Obtain an expression for the period of a satellite in a circular orbit round the earth OR Show that the square of the period of revolution of satellite is directly proportional to the cube of the orbital radius. OR Show that period of the satellite revolving around the earth depends upon mass of the earth

An artificial satellite revolves around a planet in circular orbit close to its surface. Obtain the formula for period of the satellite in terms of density U and radius R of planet.

A satellite is moving in an orbit around the earth due to

An artificial satellite is at a height of 35780 km .from the earth's surface. What is the period of revolution of this satellite?

Derive an expression for time period of a satellite orbiting very close to earth's surface in terms of mean density OR A satellite is in a low-altitude circular orbit around a spherical planet of mean density rho . Show that the period of revolution of the satellites is sqrt(3pi//rhoG)

A satellite is revolving in a circular orbit at a height 'h' from the earth's surface (radius of earth R, h <

Determine the binding energy of satellite of mass1000 kg revolving in a circular orbit around the earth. Hence, find kinetic energy and potential energy of the satellite,[mass of earth = 6 xlO^24 kg, radius of earth = 6400 km, gravitational constant G = 6.67 xlO^-11 Nm^2//kg^2 ]

A satellite of the earth is revolving in a circular orbit with uniform speed V. If the gravitational force suddenly disappears, the satellite will

A satellite is placed in a circular orbit about Earth with radius equal to half the radius of the moon's orbit. Period of rotation of the satellite is n times that of the lunar month (lunar month is the period of revolution of the moon). The value of n is