30 gm of ice at `0^@C` is placed in a calorimeter of mass 20 gm also at `0^@C`. 100 gm of water at `90^@C` is poured into the calorimeter. Find the final temperature. (specific heat of calorimeter = `0.4 cal//gm ^@C` , Specific heat of water = `0.42 cal//gm ^@C` Latent heat of fusion of ice = 80calg )

If 50 gm of water at 0^@C is added to 250 gm of water at 90^@C . Find the final temperature

The specific heat of ice at 0^@C is

40 gm of water at 70^@C is poured into a calorimeter of mass 160 gm, which is at 20^@C . If the final temperature of the contents is 40^@C , what is the specific heat of the calorimeter? Specific heat of water = 4200 J /kg/C

Calculate the amount of heat absorbed by 100 g of ice to change into water of 30^@ C.(Latent heat of fusion of ice is 80 cal//g )

Find the heat absorbed by 25g of water at 100⁰C when converted into steam at the same temperature ? (Specific latent heat of vaporization of water = 540 cal/g)

How much steam at 100^@C will just melt 1600 g of ice at -8^@C ? (Specific heat of ice= 0.5 (cal)/g^@C , specific heat of water= 1/cal/g^@C , latent of fusion of ice = 80 cal/g , and latent heat of vaporisation of water= 540 cal/g )

The water equivalent of a calorimeter is 10 g and it contains 50 g of water at 15^@C . Some amount of ice, initially -10^@C is dropped in it and half of the ice melts till equilibrium is reached. What was the initial amount of ice that was dropped (when specific heat of ice = 0.5 cal g^-1^@C^-1, specific heat of water = 1.0 cal g^1^@C^-1 and latent heat of melting of ice =80 cal g^-1 )?

Steam at 100^@C is passed into 20 g of water at 10^@C When water acquires a temperature of 80^@C , the mass of water present will be Take specific heat of water= 1 cal g^-1^@ C^-1 and latent heat of steam = 540 cal g^-1 )

A copper sphere of mass 500 g is heated 100^@C and then introduced into copper calorimeter containing 100 g of water at 20^@C . Find the maximum temperature of the mixture, if the mass of calorimeter is 100 g and specific heat capacity is 0.1 cal//g^@C

How many grams of ice at 0^@C should be added to 200 gm. of coffee at 90^@C to cool it to 60^@C ? (Assume that coffee-cup is not heated) specific heat of water = 1 c a l / g m ∘ C , Specific heat of coffee = 1.4 c a l / g m ∘ C