Calculate the thermal resistance of 1 square metre of window glass pane that is 0.5 cm thick `(k=0.6frac(W)(m^@C))`

Calculate the specific resistance of the material of a wire having a resistance of 4.4 Omega , length 1.1 m and radius 0.2 mm.

Calculate : total resistance and R_1 = 3 Omega , R_2= 6 Omega , R_3 = 5Omega, V = 14 V.

Calculate the force required to separate the glass plates of area 10^(-2)m^(2) with a film of water 0.05 mm thickness between them (surface tension of water =70xx10^(-3)N//m) )

Calculate the electric field due to a charge of -8.0 xx 10^-8 C at a distance of 5.0 cm from it

Calculate the rate of loss of heat through a glass window of area 1000 cm2 and thickness of 4 mm, when temperature inside is 27^@ C and outside is -5^@ C . Coefficient of thermal conductivity of glass is 0.022 cal/ s cm^@ C.

Calculate the resistance per metre, at room temperature, of a constantan (alloy) wire of diameter 1.25mm. The resistivity of constant of an at room temperature is 5.0 xx 10^-7 Omega m.

What is the rate of energy loss in watt per square metre through a glass window 5 mm thick if outside temperature is -20^@ C and inside temperature is 25^@ C ? ( k_("glass") = 1 W//m K )

The resistances in the two arms of the metre bridge are 5Omega and "R "Omega , respectively. When the resistance R is shunted with an equal resistance, the new balance point is at 1.6" "l_(1) . The resistance R, is

Choose correct alternative. Two resistance of 3 Omega and 2 Omega are connected in series to a cell of emf 3 volt and internal resistance of 1 Omega . The potential difference across 3 Omega resistance will be A. 1 volt B. 0.5 volt C. 1.5 volt D. 2 volt