Prove that `B_(axis) = 2 B_(equator)` for the same distances from centre of magnet.

Prove that B axis = 2B equator.

Write a formula for B_(axis) and B_(equator) for Bar magnet?

The ratio of magnetic fields due to a bar magnet at the two axial points P_(1) and P_(2) which are separated from each other by 10 cm is 25 :2 . Point P_(1) is situated at 10 cm from the centre of the magnet. Magnetic length of the bar magnet is (Points P_(1) and P_(2) are on the same side of magnet and distance of P_(2) from the centre is greater than distance of P_(1) from the centre of magnet)

Choose the corect options. The magnetic field at a point A on the axis of a small bar magnet is equal to the field at a point B on the equator of same magnet. The ratio of distance of A and B from centre of magnet is A. 2^3 B. 2^(-1//3) C. 2^(-2//3) D. 2^(1//3)

The magnetic induction at an axial point is equal to the magnetic induction at an equatorial point. Calculate the ratio of their distances from the centre of the dipole.

The magnetic induction at a point on axis or equator is proportional to n" power of distance from centre where n is

The magnetic induction at a point P on the axis is equal to the magnetic induction at a point Q on the equator of a short magnetic dipole. What is the ratio of the distances of P and Q from the centre of the dipole?

A short magnetic dipole has magnetic moment 0.5 Am^2 . Calculate its magnetic field at a distance of 20 cm from the centre of magnetic dipole on (i) the axis (ii) the equatorial line. [ mu_o = 4pi xx 10^-7 SI units] ?

A short magnetic dipole has magnetic moment 0.5 Am2. Calculate the magnetic induction at a distance of 20 cm from the centre of the magnetic dipole on the axis and the equitorial line [ mu_o = 4pi xx 10^-7 SI unit].