The vertical and horizontal components of the earth's magnetic induction at a place are `2 xx 10^-5` T respectiveley. Calculate dip and the magnitude of the earth's magnetic induction at that place.

A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian, has its north tip pointing down at 21^@ 48^1 with the horizontal. If the horizontal component of the earth's magnetic induction at that place is 3.5 xx 10^-5 T, determine the earth's magnetic induction at that place.

A short bar magnet has magnetic moment 20 Am^2 . The axis of the magnet is in the magnetic meridian with the south pole pointing north. The horizontal component of earth's magnetic field at that place is 3 xx 10^-5 T. Find the point on the axis of the magnet at which the resultant magnetic field is zero, [such a point is called a neutral point].

At a certain place the horizontal component of the earth's magnetic field is B_(0) and the angle of dip is 45^(@) . The toyal intensity of the field at that place will be

The horizontal component of the earth's magnetic field is 0.22 Gauss and total magnetic field is 0.4 Gauss. The angle of dip. Is

In the magnetic meridian of a certain place, the horizontal component of earth magnetic field is 0.26 xx 10^-4 T and dip angle is 60^@ , what is the magnetic field of the earth at this location?

At certain place, the horizontal component of earth's magnetic field is 3.0G and the angle dip at the place is 30^(@) . The magnetic field of earth at that location

The direction of earth's magnetic field is horizontal and vertical respectively at

At a given place let angle of dip be 30^(@) then the vertical component of earth's magnetic induction is

At a particular place, horizontal and vertical components of earth's magnetic field are equal. The angle of dip at that place is…………… .