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The pH of the solution containing 10 mL ...

The pH of the solution containing 10 mL of 0.1 N NaOH and 10 mL of 0.05 N ` H_(2)SO_(4)` would be

A

1

B

0

C

7

D

` gt 7`

Text Solution

Verified by Experts

The correct Answer is:
D
Number of milliequivalents of NaOH
= Normality `xx` volume (mL) = `0.1 xx 10 =1 `
Number of milliequivalents of ` H_(2)SO_(4) = 0.05 xx 10 = 0.5 `
0.5 milliequivalent of ` H_(2)SO_(4)` gets neutralized with contains 0.5 milliequivalent of NaOH. Hence solution will be basic with PH > 7
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