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A 20 mL, urea solution of 2% (w/V) i...

A 20 mL, urea solution of 2% (w/V) is mixed with 80mL of glucose solution of 4% (w/V) at 300 K. Calculate the osmotic pressure of the solution .

A

6.02 atm

B

1.642 atm

C

4.378 atm

D

3.01 atm

Text Solution

Verified by Experts

The correct Answer is:
A

` pi = w/(MV) RT `
` = [(w/M)_("urea") + (w/M)_("glucose")]xx (RT)/V `
Now, ` w_(urea) "in" 20 mL = (2 xx 20)/(100) = 0.4 g `
` w_(" glucose") "in" 80 mL = ( 4 xx 80)/100 = 3.2 g `
` therefore = [ (0.4)/60 + (3.2)/(180)] xx ( 0.0821 xx 300 xx 1000)/(100) `
` (therefore V = 20 + 80 = 100 mL = 100/1000 L) `
` pi = 6.02 atm `
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