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The empirical formula of an organic com...

The empirical formula of an organic compound containing carbon and hydrogen is ` CH_(2)` . The mass of one litre of this organic gas is exactly to that of one litre of ` N_(2)`. Therefore, the molecular formula of the organic gas is

A

`C_(2)H_(4)`

B

`C_(3)H_(6)`

C

`C_(6)H_(12)`

D

`C_(4)H_(s)`

Text Solution

Verified by Experts

The correct Answer is:
A
Empirical formula weight ` 12 +2 xx 1 = 14 22.4 L of N_(2) = 28g `
` Rightarrow 1 L " of " N_(2) = 28/22.4 g `
Now, 1 L of organic gas = ` 28/22.4` g
` Rightarrow ` 22.4 L of organic gas = 28 g
Molecular weight of gas = 28 g
(Empirical weight) = Molecular weight
` n = 28/14 =2 `
molecular formula = ` (" Empirical formula")_(n) = (CH_(2))_(2) = C_(2)H_(4)`
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