Current is passed through two cells connected in series, the first cell contains `X(NO_3)_(3(aq))` and the second cell contains `Y(NO_(3))_(2(aq))`. The relative atomic masses of X and Y are in the ratio 1 : 2. What is the ratio of the liberated mass of X to that of Y?

Options

A. `3:2`
B. `1:2`
C. `1:3`
D. `3:1`

Answer

C

Explanation

If atomic mass of X = a, then that of Y =2a
As Eq.wt. = Atomic mass/Valency
Eq. wt. of `X=a/3`, Eq. wt. of `Y=(2a)/2` =a
According to Faraday.s second law :
`"Liberated Mass of X"/"Liberated Mass of Y"="Eq. wt. of X"/"Eq. wt. of Y"=(a//3)/a=1/3`=1:3