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Water and chlorobenzene are immiscible l...

Water and chlorobenzene are immiscible liquids. Their mixture boils at `90^@`C under a reduced pressure of `7.82 xx 10^4` Pa. The vapour pressure of pure water at `90^@C` is `7.03 xx 10^4` Pa. On weight per cent basis, chlorobenzene in the distillate is equal to (mol. wt. of chlorobenzene is 112.5 g `"mol"^(-1)`)

A

50

B

60

C

70

D

80

Text Solution

Verified by Experts

The correct Answer is:
C
`p_"mix"=7.82xx10^4` Pa
`p_(H_2O) + p_(C_6H_5Cl)=7.82xx10^4` Pa
`p_(H_2O) = 7.03xx10^4` Pa `therefore p_(C_6H_5Cl)=0.79xx10^4` Pa
`p prop n prop w/m , therefore (w_(C_6H_5Cl)xxM_(H_2O))/(w_(H_2O)xxM_(C_6H_5Cl))=p_(C_6H_5Cl)/p_(H_2O)`
`w_(C_6H_5Cl)/w_(H_2O)=(p_(C_6H_5Cl)xxM_(C_6H_5Cl))/(p_(H_2O)xxM_(H_2O))=((0.79xx10^4)xx112.5)/((7.03xx10^4)xx18)`=0.70
Weight per cent of chlorobenzene is distillate
`=0.70xx100` = 70
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Knowledge Check

  • Water and Chlorobenzene are immiscible liquids. Their mixture boils at 90^(@)C under a reduced pressure of 7.82xx10^(10) Pa. The vapour pressure of pure water at 90^(@)C is 7.03xx10^(4) Pa. On weight percent basis, chlorobenzene in the disillate is equla to :( Mol. wt. of chlorobenzen is 112.5g mol^(-1) )

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  • Water and chlorobenzene are immiscible liquids. Their mixture boils at 89^(@)C under a redued pressure of 7.7 xx10^(4)Pa . The vapour pressure of pure water at 89^(@)C is 7xx10^(4)Pa . Weight per ccent of chlorobenzene in the distillate is :

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  • A mixture of chlorobenzene and water (which are virtually immiscible) boils at 90.3 ^@C at an external pressure of 740.2 mm. The vapour pressure of pure water at 40.3 ^@C is 530.1 mm. What is the percentage weight of chlorobenzene in the distillate?

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