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The E^@ for the cell reaction , Cu((s)...

The `E^@` for the cell reaction ,
`Cu_((s)) + 2Ag_((aq))^(+) to Cu_((aq))^(2+) + 2Ag_((s))` is 0.46 V , what is its equilibrium constant ?

A

15.6

B

`4.6xx10^16`

C

`3.6xx10^15`

D

`1.56xx10^15`

Text Solution

Verified by Experts

The correct Answer is:
C
`E_"cell"^@ =0.0591/2 "log"K_c`
log `K_c=(0.46xx2)/0.0591`=15.6
`therefore K_c=3.6xx10^15`
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