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A copper disc of radius 0.1 m is rotated...

A copper disc of radius 0.1 m is rotated about its centre, with 10 revolutions per second, in a uniform magnetic field of 0.1 tesla with its plane perpendicular to the field. The e.m.f. induced across the radius of the disc is

A

`pi xx 10^(-1)` volt

B

`pi xx 10^(-2)` volt

C

`2pi xx 10^(-1)` volt

D

`2pi xx 10^(-2)` volt

Text Solution

Verified by Experts

The correct Answer is:
B

E.m.f induced across the radius of the disc is,
`e=(B omega R^(2))/(2)=(0.1 xx(2pi xx 10)xx(0.1)^(2))/(2)`
`rArr e=0.1 xx(0.1)^(2)xx pi xx10=pi xx 10^(-2)V`
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Knowledge Check

  • A copper disc of radius 0.1 m rotates about its centre with 10 revolutuion per second in a uniform magnetic field of 0.1 tesla with its plane perpendicular to the field. The emf induced across the radius of the disc is

    A
    `(pi)/(10)V`
    B
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    C
    `pixx10^(-2)V`
    D
    `2pixx10^(-2)V`
  • A copper disc of radius 0.1 m is rotated about its centre with 10 revolutions per second in a uniform magnetic field of 0.1 Twith its plane perpendicular to the field. The emf induced across the radius of the dics is

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    `pi/10 V`
    B
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  • A copper disc of radius 0.1 m is rotated about its centre with 20 revolution per second in a uniform magnetic field of 0.1 T with its plane perpendicular to the field. The emf induced across the radius of the disc is-

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    `(pi)/(20)`volt
    B
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    C
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    D
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